A discrete-time signal will often possess some form of symmetry that may be exploited in solving problems. Two symmetries of interest are as follows: A real-valued signal is said to be even if, for all indices n, x[n]=x[−n], whereas a signal is said to be odd if, for all indices n, x[n]=−x[−n]. For complex signals the symmetries of interest are slightly different namely a complex signal is conjugate symmetric if, for all indices nx[n]=x∗[−n] and a signal is said to be conjugate antisymmetric if, for all indices nx[n]=−x∗[−n].
Furthermore, any signal x[n] may be decomposed into a sum of its even part, denoted by xe[n], and its odd part, denoted by xo[n].
The even part can be constructed as xe[n]=12(x[n]+x[−n]), while the odd part can be constructed as xo[n]=12(x[n]−x[−n]).
The following equations summarize all these symmetries:
Even Conjugate-symmetric:x[n]=x[−n]x[n]=x∗[−n]Odd Conjugate-antisymmetric:x[n]=−x[−n]x[n]=−x∗[−n]General: x[n]=xe[n]+xo[n]with xe[n]=12(x[n]+x[−n])and xo[n]=12(x[n]−x[−n])
Example
If x[n]=0 for n<0, derive an expression for x[n] in terms of its even part, xe[n]=(0.8)|n|u[n].
Note that for x[n]=0 for n<0 we have xe[n]=12x[n] for n>0 and xe[n]=x[n] for n=0. From this it follows that in this case we can write x[n] in terms of its even part as follows:
x[n]={xe[n]for n=02xe[n]for n>0.
With xe[n]=(0.8)|n|u[n] this results in the following:
x[n]=δ[n]+2(0.8)nu[n−1].Note: If only the odd part is given for this case, it is not possible to recover x[n].
Example
Is the complex signal x[n]=jejnπ4 conjugate-symmetric or
-antisymmetric?
xe[n]=12(x[n]+x∗[−n])=12(jejnπ4−jejnπ4)=0
Thus, this signal x[n] is conjugate-antisymmetric.